Thanks Obscuritan for the clue..else it would have took me a long time.. There may be easy ways to do it, but this is how I did it. Used the trial and error method only at few steps.
Counting the digits, it is like this M AAA RRR SSSS V EEE NNNNN UUUUU TT P
So either N= 1 or 6 And U=6 or 1
MARS MARS VE16S VE61S 6RA16S or 1RA61S SAT6R1 SAT1R6 ---------- -------- 1EPT61E 6EPT16E
Even if you consider the largest number for each digit 9 for all (even if that is not the case), the total won’t go beyond 2,109,996. Since we have 6 as the leftmost digit in the second option, we now know, N=1 and U=6
Also, we know Sis not equal to 0. If it was the case, adding the first four digit should have given N instead of E (0+0+0+1=1)
Now, the second column from the right has 6+R+R+6. That is 12+2R. No matter what the digit R, the total will be an even number. Also, the reminder from the first column can either be 1 or 2 only. If it is 2, we will not get 1 as the answer for addition of second column. The only option is 1. If that is the case S can have only 3 or 4 as its values (1 = N & U=6. 2 won’t give the reminder 1. 7,8 & 9 will give the reminder 2. If it is 5, then E has to be 6, but we know that is not the case as U =6)
In this scenario, E can have only two values, E=0 or 3 . . . . Getting bored.. Will tell the answer
Ok..since no one answered, I will say the answer for the bullet question.. Take 1 bullet from first machine, two bullets from second, three from third and so on until you take 10 bullets from tenth machine. Just weigh it once. If all were perfect you will get 550 grams. But if the first machine was faulty making 11 g bullets, you will get 551 and if it makes 9g bullets, you will get 549 If it is the second machine, you will get 552 or 548 If it is third machine, you will get 553 or 547 and so on You just need to weigh once and you know your faulty machine.
Clear?
By the way, I like this thread the most. Something to ignite your logical part of your brain..thank u daggyone for starting it..
I did not tell that they were made of lead. It can be any material. I just put bullets in the case. I could say a plastic bottle making machine, or cork making machine or something like that..
You need to find out the faulty machine by just one weighing.
No..You can't add one at a time! When you weigh the first bullet from the first machine, your chance is over. You can only weigh once. If you are keep adding bullets, you are weighing it each time. As I explained, you can weigh only once, no matter how many bullets from any of the machines you have. Try again.
Anyway I planned to be there once and I could n't. So this time I am not promising so that I won't be in the list.
OK here comes the question.
There are 10 machines that make bullets. Every machine makes bullets weighing 10 grams, except one. The faulty machine makes bullets weighing either 9g or 11g,but we do not know whether it is actually making 9g bullets or 11g bullets. You have a weighing machine ( let it be an electronic weighing machine this time for accuracy, but you may use a traditional one too). You can take any number of bullets from any of the machines, but you can weigh the bullets only once.( yes, only one single time). You have to tell which one is the faulty machine..
Ok let me get this right. There is no mention of who turned up. Given the uncertainity of the question, we can have many answers, provided this is a serious question 1. If the extra 5 are from interstate and those turned up from vic are those who promised no one! 2. If the extra are from vic, we should remove someone from the list.
The extras can be be a mixture of interstate and vic and I loved permutations and combinations in my school.
No..You can't measure all with those four weights. I will explain if anyone ask for it or I can wait till someone comes up with the answer..what do you prefer?
I am talking about those weighing machine where you normally put "weight on one cup and you put the vegetable on the other cup and look for a steady bar that stand parallel to earth" .
One man had a weight of 40 kg. He accidentally dropped it and it break it in to four pieces. However with these four pieces he can weigh any weight from 1 to 40 kg ( only integers ie 1, 2, 3, 4....... 39, 40). What are the four weights?
silverblaze Forum Posts (56)
Why is no one curious about using our brain..? Questions and answers please...
RE: The Australian government what’s your vote?
You can be a candidate!!